Home Survival News Zanesville Ohio women with a 2 percent survival rate gets “golden buzzer”...

Zanesville Ohio women with a 2 percent survival rate gets “golden buzzer” on America’s Got Talent

0
84


Zanesville, OH(WTAP) – A woman from Zanesville wowed the judges on America’s Got Talent Tuesday night so much that she

Jane Marczewski,, who goes by the name “nightbird” is a two-time breast cancer survivor with a 2 percent chance of survival.

She sang an original song called “it’s o-k.”

The crowd and judges loved her voice…Especially Simon Cowell. She automatically advanced to the live shows later this season after he pressed the “golden buzzer” after her performance.

“It just felt so dream-like. It’s amazing to be able to sing something so personal to me and to have people connect with it on such a deep level,” Marczewski said.

She will perform again on America’s Got Talent stage in august during its live shows.

Copyright 2021 WTAP. All rights reserved.



Source link

LEAVE A REPLY

Please enter your comment!
Please enter your name here